(2a^2-4a+3)+(6a^2+4a-3)=

Solution for (2a^2-4a+3)+(6a^2+4a-3)= equation:

Simplifying
(2a2 + -4a + 3) + (6a2 + 4a + -3) = 0

Reorder the terms:
(3 + -4a + 2a2) + (6a2 + 4a + -3) = 0

Remove parenthesis around (3 + -4a + 2a2)
3 + -4a + 2a2 + (6a2 + 4a + -3) = 0

Reorder the terms:
3 + -4a + 2a2 + (-3 + 4a + 6a2) = 0

Remove parenthesis around (-3 + 4a + 6a2)
3 + -4a + 2a2 + -3 + 4a + 6a2 = 0

Reorder the terms:
3 + -3 + -4a + 4a + 2a2 + 6a2 = 0

Combine like terms: 3 + -3 = 0
0 + -4a + 4a + 2a2 + 6a2 = 0
-4a + 4a + 2a2 + 6a2 = 0

Combine like terms: -4a + 4a = 0
0 + 2a2 + 6a2 = 0
2a2 + 6a2 = 0

Combine like terms: 2a2 + 6a2 = 8a2
8a2 = 0

Solving
8a2 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Divide each side by '8'.
a2 = 0

Simplifying
a2 = 0

Take the square root of each side:
a = {0}